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Balancing EquationsThe trick with this one is to treat the phosphate ion (PO_{4}^{3)} as an element, and not break it into two individual elements.If you do that, you get:
Fe: 1a + 0b 3c = 0d Note that you do not have a square matrix for Matrix A. Following the regular procedures, you should get a 4 x 3 matrix (four rows, three columns). You can make it square without changing the algorithm by adding a column of 1's at the end of the matrix.
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