Course Chapters
Section Tests
Online Calculators Linear Least Squares Regression Newton's Method Equation Solver
Related Information Links

Problem 3 Solution
Solution Steps for Part (a):If a sample of methane contains 1565 atoms, how much carbon and hydrogen are present?
Answer:This is different from the last problem because we are given the total number of atoms instead of the amount present of one of them. What do we know?
Let's cross multiply this proportion as usual to get:
So, we can substitute 4 carbons in for the hydrogen in the first equation:
Put the carbons together: (4 and 1 makes 5)
So what's left must be hydrogen: 1565  313 = 1252. Solution Steps for Part (b):Can a sample contain 1566 atoms?
Answer:Look at the work from part (a): We know that the total number of atoms must be divisible by 5.Think about what a ratio tells you when you can't have fractional parts of the items: The items must come in groups of 5  1 carbon for every 4 hydrogens in this case. Using this idea, there can't be 1566 atoms because 1566 is not divisible by 5 because 5 carbon = 1565(total). Try it on your calculator; do you get a whole number? No! 
Copyright © 19962008 Shodor
Please direct questions and comments about this page to
WebMaster@shodor.org