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Practice Problem 2 Solution:

If 2.0 moles of sucrose weighting 684 grams is put in 1000 grams of water
and is then dissolved, what would be the molality of the solution? 

Answer = 2.00 m

In this problem we use the equation for molality.
Molality=moles of solute/kilograms of solvent
We know the moles of solute is 2 and the solvent weighs 1.00 kilograms. Therefore 2 moles/1.00 kilograms = 2.00 m

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