Nomenclature Formula Solutions

The key to solving these correctly is knowing the charges on the ions and correctly placing them together. For example, in Problem 1, aluminum has a +3 charge while fluoride has a -1 charge. To make the charges balance, we must have three fluorides for every aluminum. The other problems follow the same logic. Problems 12 and 13 are acids so they must be dealt with in a slightly different way.

aluminum fluroide: AlF₃
carbon tetracloride: CCl₄
strontium nitrate: Sr(NO₃)₂
sodium bisulfate: Na HSO₄
iron (III) oxide: Fe₂O₃
mercury (II) nitrate: Hg(NO₃)₂
sodium sulfite: Na₂SO₃
ammonium dichromate: (NH₄)₂Cr₂O₇
magnesium acetate: Mg(C₂H₃O₂)₂
zinc hydroxide: Zn(OH)₂
nitric acid: HNO₃
hypochlorous acid: HClO
phosphoric acid: H₃PO₄
aluminum nitrate: Al(NO₃)₃

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Developed by

Shodor
in cooperation with the Department of Chemistry,
The University of North Carolina at Chapel Hill